16x^2-225x-225=0

Solution for 16x^2-225x-225=0 equation:

16x^2-225x-225=0

a = 16; b = -225; c = -225;
Δ = b2-4ac
Δ = -2252-4·16·(-225)
Δ = 65025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{65025}=255$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-225)-255}{2*16}=\frac{-30}{32}
=-15/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-225)+255}{2*16}=\frac{480}{32}
=15
$